Base | Representation |
---|---|
bin | 10010011100100001… |
… | …11010001100100001 |
3 | 221120011020000120121 |
4 | 21032100322030201 |
5 | 130240131140423 |
6 | 4314355240241 |
7 | 500256012202 |
oct | 111620721441 |
9 | 27504200517 |
10 | 9902990113 |
11 | 4221a86055 |
12 | 1b045a9081 |
13 | c1a882983 |
14 | 69d30d5a9 |
15 | 3ce5e945d |
hex | 24e43a321 |
9902990113 has 2 divisors, whose sum is σ = 9902990114. Its totient is φ = 9902990112.
The previous prime is 9902990081. The next prime is 9902990117. The reversal of 9902990113 is 3110992099.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7086777489 + 2816212624 = 84183^2 + 53068^2 .
It is an emirp because it is prime and its reverse (3110992099) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 9902990113 - 25 = 9902990081 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 9902990113.
It is not a weakly prime, because it can be changed into another prime (9902990117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4951495056 + 4951495057.
It is an arithmetic number, because the mean of its divisors is an integer number (4951495057).
Almost surely, 29902990113 is an apocalyptic number.
It is an amenable number.
9902990113 is a deficient number, since it is larger than the sum of its proper divisors (1).
9902990113 is an equidigital number, since it uses as much as digits as its factorization.
9902990113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39366, while the sum is 43.
The square root of 9902990113 is about 99513.7684594448. The cubic root of 9902990113 is about 2147.4453242906.
The spelling of 9902990113 in words is "nine billion, nine hundred two million, nine hundred ninety thousand, one hundred thirteen".
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