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99030227537 = 99667993611
BaseRepresentation
bin101110000111010101…
…0010101101001010001
3100110121120211210112002
41130032222111221101
53110303214240122
6113254401243345
710104030021353
oct1341652255121
9313546753462
1099030227537
1138aa8a8875a
1217239033555
139452926c97
144b163410d3
152899029992
hex170ea95a51

99030227537 has 4 divisors (see below), whose sum is σ = 99031320816. Its totient is φ = 99029134260.

The previous prime is 99030227531. The next prime is 99030227563. The reversal of 99030227537 is 73572203099.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 73572203099 = 171894280191.

It is a cyclic number.

It is not a de Polignac number, because 99030227537 - 212 = 99030223441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 99030227491 and 99030227500.

It is not an unprimeable number, because it can be changed into a prime (99030227531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397139 + ... + 596472.

It is an arithmetic number, because the mean of its divisors is an integer number (24757830204).

Almost surely, 299030227537 is an apocalyptic number.

It is an amenable number.

99030227537 is a deficient number, since it is larger than the sum of its proper divisors (1093279).

99030227537 is an equidigital number, since it uses as much as digits as its factorization.

99030227537 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1093278.

The product of its (nonzero) digits is 714420, while the sum is 47.

The spelling of 99030227537 in words is "ninety-nine billion, thirty million, two hundred twenty-seven thousand, five hundred thirty-seven".

Divisors: 1 99667 993611 99030227537