Search a number
-
+
990535433 is a prime number
BaseRepresentation
bin111011000010100…
…101111100001001
32120000212102011112
4323002211330021
54012034113213
6242142340105
733355261256
oct7302457411
92500772145
10990535433
11469149a28
1223788a635
1312a2a5254
14957a642d
155be61ea8
hex3b0a5f09

990535433 has 2 divisors, whose sum is σ = 990535434. Its totient is φ = 990535432.

The previous prime is 990535393. The next prime is 990535439. The reversal of 990535433 is 334535099.

990535433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 938074384 + 52461049 = 30628^2 + 7243^2 .

It is a cyclic number.

It is not a de Polignac number, because 990535433 - 218 = 990273289 is a prime.

It is not a weakly prime, because it can be changed into another prime (990535439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495267716 + 495267717.

It is an arithmetic number, because the mean of its divisors is an integer number (495267717).

Almost surely, 2990535433 is an apocalyptic number.

It is an amenable number.

990535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

990535433 is an equidigital number, since it uses as much as digits as its factorization.

990535433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 218700, while the sum is 41.

The square root of 990535433 is about 31472.7728838754. The cubic root of 990535433 is about 996.8351385521.

The spelling of 990535433 in words is "nine hundred ninety million, five hundred thirty-five thousand, four hundred thirty-three".