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99120953 is a prime number
BaseRepresentation
bin1011110100001…
…11011100111001
320220111212101102
411322013130321
5200333332303
613500301145
72312341241
oct572073471
9226455342
1099120953
1150a51048
12292417b5
13176c6669
14d242b21
158a7e288
hex5e87739

99120953 has 2 divisors, whose sum is σ = 99120954. Its totient is φ = 99120952.

The previous prime is 99120943. The next prime is 99120997. The reversal of 99120953 is 35902199.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86638864 + 12482089 = 9308^2 + 3533^2 .

It is a cyclic number.

It is not a de Polignac number, because 99120953 - 24 = 99120937 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (99120943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49560476 + 49560477.

It is an arithmetic number, because the mean of its divisors is an integer number (49560477).

Almost surely, 299120953 is an apocalyptic number.

It is an amenable number.

99120953 is a deficient number, since it is larger than the sum of its proper divisors (1).

99120953 is an equidigital number, since it uses as much as digits as its factorization.

99120953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21870, while the sum is 38.

The square root of 99120953 is about 9955.9506326619. The cubic root of 99120953 is about 462.7948203543.

The spelling of 99120953 in words is "ninety-nine million, one hundred twenty thousand, nine hundred fifty-three".