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991301000593 is a prime number
BaseRepresentation
bin11100110110011100010…
…01001101110110010001
310111202201110201110122211
432123032021031312101
5112220141024004333
62035221500432121
7131422235322511
oct16331611156621
93452643643584
10991301000593
11352454631992
12140154848641
137262cca6907
1435d9cdc5841
151abbcbe4ecd
hexe6ce24dd91

991301000593 has 2 divisors, whose sum is σ = 991301000594. Its totient is φ = 991301000592.

The previous prime is 991301000581. The next prime is 991301000603. The reversal of 991301000593 is 395000103199.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 616589293824 + 374711706769 = 785232^2 + 612137^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-991301000593 is a prime.

It is not a weakly prime, because it can be changed into another prime (991301000513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495650500296 + 495650500297.

It is an arithmetic number, because the mean of its divisors is an integer number (495650500297).

Almost surely, 2991301000593 is an apocalyptic number.

It is an amenable number.

991301000593 is a deficient number, since it is larger than the sum of its proper divisors (1).

991301000593 is an equidigital number, since it uses as much as digits as its factorization.

991301000593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32805, while the sum is 40.

The spelling of 991301000593 in words is "nine hundred ninety-one billion, three hundred one million, five hundred ninety-three", and thus it is an aban number.