Base | Representation |
---|---|
bin | 11100110110011100010… |
… | …01001101111000001001 |
3 | 10111202201110201110211021 |
4 | 32123032021031320021 |
5 | 112220141024010323 |
6 | 2035221500432441 |
7 | 131422235323042 |
oct | 16331611157011 |
9 | 3452643643737 |
10 | 991301000713 |
11 | 352454631a91 |
12 | 140154848721 |
13 | 7262cca699a |
14 | 35d9cdc58c9 |
15 | 1abbcbe505d |
hex | e6ce24de09 |
991301000713 has 2 divisors, whose sum is σ = 991301000714. Its totient is φ = 991301000712.
The previous prime is 991301000671. The next prime is 991301000759. The reversal of 991301000713 is 317000103199.
991301000713 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 877993362169 + 113307638544 = 937013^2 + 336612^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-991301000713 is a prime.
It is not a weakly prime, because it can be changed into another prime (991301000413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495650500356 + 495650500357.
It is an arithmetic number, because the mean of its divisors is an integer number (495650500357).
Almost surely, 2991301000713 is an apocalyptic number.
It is an amenable number.
991301000713 is a deficient number, since it is larger than the sum of its proper divisors (1).
991301000713 is an equidigital number, since it uses as much as digits as its factorization.
991301000713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 34.
The spelling of 991301000713 in words is "nine hundred ninety-one billion, three hundred one million, seven hundred thirteen", and thus it is an aban number.
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