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9913304817121 is a prime number
BaseRepresentation
bin1001000001000001111100…
…0000110001110111100001
31022002200222020221122112011
42100100133000301313201
52244404422013121441
633030035342232521
72042132635425136
oct220203700616741
938080866848464
109913304817121
113182233147a52
121141321885741
1356ba88c14044
14263b4110258d
15122d03cbb581
hex9041f031de1

9913304817121 has 2 divisors, whose sum is σ = 9913304817122. Its totient is φ = 9913304817120.

The previous prime is 9913304816911. The next prime is 9913304817161. The reversal of 9913304817121 is 1217184033199.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5543971630096 + 4369333187025 = 2354564^2 + 2090295^2 .

It is an emirp because it is prime and its reverse (1217184033199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9913304817121 - 219 = 9913304292833 is a prime.

It is a super-2 number, since 2×99133048171212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (9913304817161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4956652408560 + 4956652408561.

It is an arithmetic number, because the mean of its divisors is an integer number (4956652408561).

Almost surely, 29913304817121 is an apocalyptic number.

It is an amenable number.

9913304817121 is a deficient number, since it is larger than the sum of its proper divisors (1).

9913304817121 is an equidigital number, since it uses as much as digits as its factorization.

9913304817121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 49.

The spelling of 9913304817121 in words is "nine trillion, nine hundred thirteen billion, three hundred four million, eight hundred seventeen thousand, one hundred twenty-one".