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99144132851 is a prime number
BaseRepresentation
bin101110001010101110…
…0110110100011110011
3100110220112011210020102
41130111130312203303
53111021344222401
6113313550503015
710106612140001
oct1342534664363
9313815153212
1099144132851
1139057307485
121726b204a6b
1394703c8a8a
144b27511a71
1528a402956b
hex17157368f3

99144132851 has 2 divisors, whose sum is σ = 99144132852. Its totient is φ = 99144132850.

The previous prime is 99144132847. The next prime is 99144132931. The reversal of 99144132851 is 15823144199.

It is a weak prime.

It is an emirp because it is prime and its reverse (15823144199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99144132851 - 22 = 99144132847 is a prime.

It is a super-3 number, since 3×991441328513 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 99144132796 and 99144132805.

It is not a weakly prime, because it can be changed into another prime (99144132151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49572066425 + 49572066426.

It is an arithmetic number, because the mean of its divisors is an integer number (49572066426).

Almost surely, 299144132851 is an apocalyptic number.

99144132851 is a deficient number, since it is larger than the sum of its proper divisors (1).

99144132851 is an equidigital number, since it uses as much as digits as its factorization.

99144132851 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 311040, while the sum is 47.

The spelling of 99144132851 in words is "ninety-nine billion, one hundred forty-four million, one hundred thirty-two thousand, eight hundred fifty-one".