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9926108754953 is a prime number
BaseRepresentation
bin1001000001110001101000…
…1011111011010000001001
31022010221000120211002020212
42100130122023323100021
52300112132320124303
633035554051130505
72043065141206016
oct220343213732011
938127016732225
109926108754953
113187703689a56
1211438b58a3a35
135700497a9c11
142645d77d270d
15123302de0ad8
hex9071a2fb409

9926108754953 has 2 divisors, whose sum is σ = 9926108754954. Its totient is φ = 9926108754952.

The previous prime is 9926108754949. The next prime is 9926108754971. The reversal of 9926108754953 is 3594578016299.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8725477947664 + 1200630807289 = 2953892^2 + 1095733^2 .

It is a cyclic number.

It is not a de Polignac number, because 9926108754953 - 22 = 9926108754949 is a prime.

It is not a weakly prime, because it can be changed into another prime (9926108754973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4963054377476 + 4963054377477.

It is an arithmetic number, because the mean of its divisors is an integer number (4963054377477).

It is a 1-persistent number, because it is pandigital, but 2⋅9926108754953 = 19852217509906 is not.

Almost surely, 29926108754953 is an apocalyptic number.

It is an amenable number.

9926108754953 is a deficient number, since it is larger than the sum of its proper divisors (1).

9926108754953 is an equidigital number, since it uses as much as digits as its factorization.

9926108754953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 146966400, while the sum is 68.

The spelling of 9926108754953 in words is "nine trillion, nine hundred twenty-six billion, one hundred eight million, seven hundred fifty-four thousand, nine hundred fifty-three".