Base | Representation |
---|---|
bin | 11100111010011110111… |
… | …11000110111100001011 |
3 | 10111222022200221212200111 |
4 | 32131033133012330023 |
5 | 112234112034002311 |
6 | 2040221055215151 |
7 | 131530065112405 |
oct | 16351737067413 |
9 | 3458280855614 |
10 | 993471000331 |
11 | 3533685308a7 |
12 | 14065b5174b7 |
13 | 728b7733124 |
14 | 36127293b75 |
15 | 1ac98487d21 |
hex | e74f7c6f0b |
993471000331 has 2 divisors, whose sum is σ = 993471000332. Its totient is φ = 993471000330.
The previous prime is 993471000307. The next prime is 993471000341. The reversal of 993471000331 is 133000174399.
It is a strong prime.
It is an emirp because it is prime and its reverse (133000174399) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 993471000331 - 231 = 991323516683 is a prime.
It is a super-2 number, since 2×9934710003312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (993471000341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496735500165 + 496735500166.
It is an arithmetic number, because the mean of its divisors is an integer number (496735500166).
Almost surely, 2993471000331 is an apocalyptic number.
993471000331 is a deficient number, since it is larger than the sum of its proper divisors (1).
993471000331 is an equidigital number, since it uses as much as digits as its factorization.
993471000331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 61236, while the sum is 40.
The spelling of 993471000331 in words is "nine hundred ninety-three billion, four hundred seventy-one million, three hundred thirty-one", and thus it is an aban number.
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