Base | Representation |
---|---|
bin | 10010100000011101… |
… | …11000100010101001 |
3 | 221122110100210010022 |
4 | 21100032320202221 |
5 | 130322104412411 |
6 | 4321535130225 |
7 | 501136502222 |
oct | 112016704251 |
9 | 27573323108 |
10 | 9936013481 |
11 | 4239690a99 |
12 | 1b13673975 |
13 | c24675b24 |
14 | 6a3868249 |
15 | 3d246dedb |
hex | 2503b88a9 |
9936013481 has 2 divisors, whose sum is σ = 9936013482. Its totient is φ = 9936013480.
The previous prime is 9936013361. The next prime is 9936013523. The reversal of 9936013481 is 1843106399.
9936013481 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9236939881 + 699073600 = 96109^2 + 26440^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-9936013481 is a prime.
It is a super-2 number, since 2×99360134812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (9936013181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4968006740 + 4968006741.
It is an arithmetic number, because the mean of its divisors is an integer number (4968006741).
Almost surely, 29936013481 is an apocalyptic number.
It is an amenable number.
9936013481 is a deficient number, since it is larger than the sum of its proper divisors (1).
9936013481 is an equidigital number, since it uses as much as digits as its factorization.
9936013481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 44.
The square root of 9936013481 is about 99679.5539767309. The cubic root of 9936013481 is about 2149.8296948931.
The spelling of 9936013481 in words is "nine billion, nine hundred thirty-six million, thirteen thousand, four hundred eighty-one".
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