9940283 has 2 divisors, whose sum is σ = 9940284. Its totient is φ = 9940282.

The previous prime is 9940279. The next prime is 9940297. The reversal of 9940283 is 3820499.

It is a weak prime.

It is an emirp because it is prime and its reverse (3820499) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9940283 - 2² = 9940279 is a prime.

It is a super-2 number, since 2×9940283² = 197618452240178, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (9900283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4970141 + 4970142.

It is an arithmetic number, because the mean of its divisors is an integer number (4970142).

Almost surely, 2^9940283 is an apocalyptic number.

9940283 is a deficient number, since it is larger than the sum of its proper divisors (1).

9940283 is an equidigital number, since it uses as much as digits as its factorization.

9940283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The square root of 9940283 is about 3152.8214348421. The cubic root of 9940283 is about 215.0137579081.

The spelling of 9940283 in words is "nine million, nine hundred forty thousand, two hundred eighty-three".