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9940433 is a prime number
BaseRepresentation
bin100101111010…
…110111010001
3200201000201012
4211322313101
510021043213
6553020305
7150330566
oct45726721
920630635
109940433
11567a438
1233b4695
1320a0719
14146a86d
15d154a8
hex97add1

9940433 has 2 divisors, whose sum is σ = 9940434. Its totient is φ = 9940432.

The previous prime is 9940397. The next prime is 9940451. The reversal of 9940433 is 3340499.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9935104 + 5329 = 3152^2 + 73^2 .

It is an emirp because it is prime and its reverse (3340499) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9940433 - 26 = 9940369 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 9940433.

It is not a weakly prime, because it can be changed into another prime (9930433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4970216 + 4970217.

It is an arithmetic number, because the mean of its divisors is an integer number (4970217).

Almost surely, 29940433 is an apocalyptic number.

It is an amenable number.

9940433 is a deficient number, since it is larger than the sum of its proper divisors (1).

9940433 is an equidigital number, since it uses as much as digits as its factorization.

9940433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 32.

The square root of 9940433 is about 3152.8452229692. The cubic root of 9940433 is about 215.0148394300.

The spelling of 9940433 in words is "nine million, nine hundred forty thousand, four hundred thirty-three".