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99455320313 is a prime number
BaseRepresentation
bin101110010011111111…
…1111100000011111001
3100111201012201202011222
41130213333330003321
53112141030222223
6113404504401425
710120411163036
oct1344777740371
9314635652158
1099455320313
11391a6a321a8
1217337476275
1394bca12a7b
144b5699838d
1528c14e80c8
hex1727ffc0f9

99455320313 has 2 divisors, whose sum is σ = 99455320314. Its totient is φ = 99455320312.

The previous prime is 99455320277. The next prime is 99455320331. The reversal of 99455320313 is 31302355499.

Together with next prime (99455320331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62056788544 + 37398531769 = 249112^2 + 193387^2 .

It is a cyclic number.

It is not a de Polignac number, because 99455320313 - 210 = 99455319289 is a prime.

It is a super-2 number, since 2×994553203132 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (99455320333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49727660156 + 49727660157.

It is an arithmetic number, because the mean of its divisors is an integer number (49727660157).

Almost surely, 299455320313 is an apocalyptic number.

It is an amenable number.

99455320313 is a deficient number, since it is larger than the sum of its proper divisors (1).

99455320313 is an equidigital number, since it uses as much as digits as its factorization.

99455320313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 437400, while the sum is 44.

The spelling of 99455320313 in words is "ninety-nine billion, four hundred fifty-five million, three hundred twenty thousand, three hundred thirteen".