Base | Representation |
---|---|
bin | 11100111101011110000… |
… | …10000100010101110011 |
3 | 10112010110102021201011121 |
4 | 32132233002010111303 |
5 | 112300402421001433 |
6 | 2041044121123111 |
7 | 131614601305501 |
oct | 16365702042563 |
9 | 3463412251147 |
10 | 995074000243 |
11 | 354010371414 |
12 | 140a28329497 |
13 | 72ab187949b |
14 | 3623a129671 |
15 | 1ad3e07ac2d |
hex | e7af084573 |
995074000243 has 2 divisors, whose sum is σ = 995074000244. Its totient is φ = 995074000242.
The previous prime is 995074000237. The next prime is 995074000267. The reversal of 995074000243 is 342000470599.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 995074000243 - 213 = 995073992051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 995074000243.
It is not a weakly prime, because it can be changed into another prime (995074000343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497537000121 + 497537000122.
It is an arithmetic number, because the mean of its divisors is an integer number (497537000122).
Almost surely, 2995074000243 is an apocalyptic number.
995074000243 is a deficient number, since it is larger than the sum of its proper divisors (1).
995074000243 is an equidigital number, since it uses as much as digits as its factorization.
995074000243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 272160, while the sum is 43.
The spelling of 995074000243 in words is "nine hundred ninety-five billion, seventy-four million, two hundred forty-three", and thus it is an aban number.
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