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995121084131 is a prime number
BaseRepresentation
bin11100111101100011101…
…01101011011011100011
310112010120200212211010022
432132301311223123203
5112301001444143011
62041052522224055
7131616012436346
oct16366165533343
93463520784108
10995121084131
11354034a00219
12140a4005502b
1372abb553485
14362424a445d
151ad4327b8db
hexe7b1d6b6e3

995121084131 has 2 divisors, whose sum is σ = 995121084132. Its totient is φ = 995121084130.

The previous prime is 995121084071. The next prime is 995121084149. The reversal of 995121084131 is 131480121599.

It is a strong prime.

It is an emirp because it is prime and its reverse (131480121599) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 995121084131 - 222 = 995116889827 is a prime.

It is a super-3 number, since 3×9951210841313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (995121084431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497560542065 + 497560542066.

It is an arithmetic number, because the mean of its divisors is an integer number (497560542066).

Almost surely, 2995121084131 is an apocalyptic number.

995121084131 is a deficient number, since it is larger than the sum of its proper divisors (1).

995121084131 is an equidigital number, since it uses as much as digits as its factorization.

995121084131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 44.

The spelling of 995121084131 in words is "nine hundred ninety-five billion, one hundred twenty-one million, eighty-four thousand, one hundred thirty-one".