99540829121 has 2 divisors, whose sum is σ = 99540829122. Its totient is φ = 99540829120.

The previous prime is 99540829081. The next prime is 99540829127. The reversal of 99540829121 is 12192804599.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99540250000 + 579121 = 315500^2 + 761^2 .

It is an emirp because it is prime and its reverse (12192804599) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99540829121 - 2¹⁴ = 99540812737 is a prime.

It is a super-3 number, since 3×99540829121³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 99540829121.

It is not a weakly prime, because it can be changed into another prime (99540829127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49770414560 + 49770414561.

It is an arithmetic number, because the mean of its divisors is an integer number (49770414561).

Almost surely, 2^99540829121 is an apocalyptic number.

It is an amenable number.

99540829121 is a deficient number, since it is larger than the sum of its proper divisors (1).

99540829121 is an equidigital number, since it uses as much as digits as its factorization.

99540829121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 50.

The spelling of 99540829121 in words is "ninety-nine billion, five hundred forty million, eight hundred twenty-nine thousand, one hundred twenty-one".