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9955003 is a prime number
BaseRepresentation
bin100101111110…
…011010111011
3200201202200211
4211332122323
510022030003
6553211551
7150421222
oct45763273
920652624
109955003
11568a383
123400bb7
1320a7246
141471cb9
15d1996d
hex97e6bb

9955003 has 2 divisors, whose sum is σ = 9955004. Its totient is φ = 9955002.

The previous prime is 9954991. The next prime is 9955009. The reversal of 9955003 is 3005599.

It is a strong prime.

It is an emirp because it is prime and its reverse (3005599) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9955003 - 29 = 9954491 is a prime.

It is an Ulam number.

It is not a weakly prime, because it can be changed into another prime (9955009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4977501 + 4977502.

It is an arithmetic number, because the mean of its divisors is an integer number (4977502).

Almost surely, 29955003 is an apocalyptic number.

9955003 is a deficient number, since it is larger than the sum of its proper divisors (1).

9955003 is an equidigital number, since it uses as much as digits as its factorization.

9955003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6075, while the sum is 31.

The square root of 9955003 is about 3155.1549882692. The cubic root of 9955003 is about 215.1198394456.

The spelling of 9955003 in words is "nine million, nine hundred fifty-five thousand, three".