Base | Representation |
---|---|
bin | 101110011010101111… |
… | …1100100001111010001 |
3 | 100112021222201210112001 |
4 | 1130311133210033101 |
5 | 3113122004341103 |
6 | 113443153034001 |
7 | 10126130412226 |
oct | 1346537441721 |
9 | 315258653461 |
10 | 99681715153 |
11 | 39302802a79 |
12 | 1739b255901 |
13 | 95278ac107 |
14 | 4b78a8b94d |
15 | 28d631801d |
hex | 17357e43d1 |
99681715153 has 2 divisors, whose sum is σ = 99681715154. Its totient is φ = 99681715152.
The previous prime is 99681715033. The next prime is 99681715157. The reversal of 99681715153 is 35151718699.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95738879889 + 3942835264 = 309417^2 + 62792^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-99681715153 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 99681715094 and 99681715103.
It is not a weakly prime, because it can be changed into another prime (99681715157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49840857576 + 49840857577.
It is an arithmetic number, because the mean of its divisors is an integer number (49840857577).
Almost surely, 299681715153 is an apocalyptic number.
It is an amenable number.
99681715153 is a deficient number, since it is larger than the sum of its proper divisors (1).
99681715153 is an equidigital number, since it uses as much as digits as its factorization.
99681715153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2041200, while the sum is 55.
The spelling of 99681715153 in words is "ninety-nine billion, six hundred eighty-one million, seven hundred fifteen thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •