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99682957433 is a prime number
BaseRepresentation
bin101110011010110010…
…0010011100001111001
3100112022002001220121102
41130311210103201321
53113122314114213
6113443235421145
710126144105103
oct1346544234171
9315262056542
1099682957433
1139303481354
121739b7547b5
139527c256a7
144b78cd2573
1528d64b1158
hex1735913879

99682957433 has 2 divisors, whose sum is σ = 99682957434. Its totient is φ = 99682957432.

The previous prime is 99682957403. The next prime is 99682957471. The reversal of 99682957433 is 33475928699.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75222935824 + 24460021609 = 274268^2 + 156397^2 .

It is a cyclic number.

It is not a de Polignac number, because 99682957433 - 26 = 99682957369 is a prime.

It is a super-4 number, since 4×996829574334 (a number of 45 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 99682957433.

It is not a weakly prime, because it can be changed into another prime (99682957403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49841478716 + 49841478717.

It is an arithmetic number, because the mean of its divisors is an integer number (49841478717).

Almost surely, 299682957433 is an apocalyptic number.

It is an amenable number.

99682957433 is a deficient number, since it is larger than the sum of its proper divisors (1).

99682957433 is an equidigital number, since it uses as much as digits as its factorization.

99682957433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 88179840, while the sum is 65.

The spelling of 99682957433 in words is "ninety-nine billion, six hundred eighty-two million, nine hundred fifty-seven thousand, four hundred thirty-three".