Base | Representation |
---|---|
bin | 11101000100100100110… |
… | …01110001111101010001 |
3 | 10112111022021012201020202 |
4 | 32202102121301331101 |
5 | 112331210443110213 |
6 | 2042514430144545 |
7 | 132111251246231 |
oct | 16422231617521 |
9 | 3474267181222 |
10 | 998888644433 |
11 | 355698665019 |
12 | 141711952155 |
13 | 7326bc702b4 |
14 | 364bc9cdcc1 |
15 | 1aeb3ddab58 |
hex | e892671f51 |
998888644433 has 2 divisors, whose sum is σ = 998888644434. Its totient is φ = 998888644432.
The previous prime is 998888644427. The next prime is 998888644463. The reversal of 998888644433 is 334446888899.
998888644433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 979846576384 + 19042068049 = 989872^2 + 137993^2 .
It is a cyclic number.
It is not a de Polignac number, because 998888644433 - 210 = 998888643409 is a prime.
It is a nialpdrome in base 10.
It is not a weakly prime, because it can be changed into another prime (998888644463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499444322216 + 499444322217.
It is an arithmetic number, because the mean of its divisors is an integer number (499444322217).
Almost surely, 2998888644433 is an apocalyptic number.
It is an amenable number.
998888644433 is a deficient number, since it is larger than the sum of its proper divisors (1).
998888644433 is an equidigital number, since it uses as much as digits as its factorization.
998888644433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1146617856, while the sum is 74.
The spelling of 998888644433 in words is "nine hundred ninety-eight billion, eight hundred eighty-eight million, six hundred forty-four thousand, four hundred thirty-three".
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