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999113243 is a prime number
BaseRepresentation
bin111011100011010…
…100001000011011
32120122000012201012
4323203110020123
54021233110433
6243050244135
733521215412
oct7343241033
92518005635
10999113243
11472a78627
1223a72664b
1312bcb968b
149699a479
155caa8848
hex3b8d421b

999113243 has 2 divisors, whose sum is σ = 999113244. Its totient is φ = 999113242.

The previous prime is 999113221. The next prime is 999113267. The reversal of 999113243 is 342311999.

999113243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 999113243 - 214 = 999096859 is a prime.

It is equal to p50804969 and since 999113243 and 50804969 have the same sum of digits, it is a Honaker prime.

It is a self number, because there is not a number n which added to its sum of digits gives 999113243.

It is not a weakly prime, because it can be changed into another prime (999113743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499556621 + 499556622.

It is an arithmetic number, because the mean of its divisors is an integer number (499556622).

Almost surely, 2999113243 is an apocalyptic number.

999113243 is a deficient number, since it is larger than the sum of its proper divisors (1).

999113243 is an equidigital number, since it uses as much as digits as its factorization.

999113243 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 52488, while the sum is 41.

The square root of 999113243 is about 31608.7526327756. The cubic root of 999113243 is about 999.7043269194.

The spelling of 999113243 in words is "nine hundred ninety-nine million, one hundred thirteen thousand, two hundred forty-three".