Base | Representation |
---|---|
bin | 101110100010100110… |
… | …1001110010001000001 |
3 | 100112222100210102120222 |
4 | 1131011031032101001 |
5 | 3114142001421032 |
6 | 113525251312425 |
7 | 10135511250533 |
oct | 1350515162101 |
9 | 315870712528 |
10 | 99945342017 |
11 | 394285a3814 |
12 | 174535ab715 |
13 | 956a3b3141 |
14 | 4ba1ab3853 |
15 | 28ee53ea12 |
hex | 174534e441 |
99945342017 has 2 divisors, whose sum is σ = 99945342018. Its totient is φ = 99945342016.
The previous prime is 99945342011. The next prime is 99945342037. The reversal of 99945342017 is 71024354999.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84593140801 + 15352201216 = 290849^2 + 123904^2 .
It is a cyclic number.
It is not a de Polignac number, because 99945342017 - 218 = 99945079873 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 99945342017.
It is not a weakly prime, because it can be changed into another prime (99945342011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49972671008 + 49972671009.
It is an arithmetic number, because the mean of its divisors is an integer number (49972671009).
Almost surely, 299945342017 is an apocalyptic number.
It is an amenable number.
99945342017 is a deficient number, since it is larger than the sum of its proper divisors (1).
99945342017 is an equidigital number, since it uses as much as digits as its factorization.
99945342017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 99945342017 in words is "ninety-nine billion, nine hundred forty-five million, three hundred forty-two thousand, seventeen".
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