Base | Representation |
---|---|
bin | 10110101110101111110000… |
… | …001001000000001110000001 |
3 | 111002221222110212021220202021 |
4 | 112232233300021000032001 |
5 | 101100344304013101213 |
6 | 552341145514121441 |
7 | 30025356513346225 |
oct | 2656576011001601 |
9 | 432858425256667 |
10 | 99969392706433 |
11 | 29942865a93538 |
12 | b2668a3420281 |
13 | 43a20c5000553 |
14 | 1a98789c82785 |
15 | b856776d6d8d |
hex | 5aebf0240381 |
99969392706433 has 2 divisors, whose sum is σ = 99969392706434. Its totient is φ = 99969392706432.
The previous prime is 99969392706413. The next prime is 99969392706511. The reversal of 99969392706433 is 33460729396999.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60182654031504 + 39786738674929 = 7757748^2 + 6307673^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-99969392706433 is a prime.
It is not a weakly prime, because it can be changed into another prime (99969392706413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49984696353216 + 49984696353217.
It is an arithmetic number, because the mean of its divisors is an integer number (49984696353217).
Almost surely, 299969392706433 is an apocalyptic number.
It is an amenable number.
99969392706433 is a deficient number, since it is larger than the sum of its proper divisors (1).
99969392706433 is an equidigital number, since it uses as much as digits as its factorization.
99969392706433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3214155168, while the sum is 79.
The spelling of 99969392706433 in words is "ninety-nine trillion, nine hundred sixty-nine billion, three hundred ninety-two million, seven hundred six thousand, four hundred thirty-three".
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