99992300000033 has 4 divisors (see below), whose sum is σ = 114276914285760. Its totient is φ = 85707685714308.

The previous prime is 99992300000011. The next prime is 99992300000059. The reversal of 99992300000033 is 33000000329999.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 99992300000033 - 2⁸ = 99992299999777 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (99992300080033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7142307142853 + ... + 7142307142866.

It is an arithmetic number, because the mean of its divisors is an integer number (28569228571440).

Almost surely, 2^{99992300000033} is an apocalyptic number.

It is an amenable number.

99992300000033 is a deficient number, since it is larger than the sum of its proper divisors (14284614285727).

99992300000033 is a wasteful number, since it uses less digits than its factorization.

99992300000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14284614285726.

The product of its (nonzero) digits is 354294, while the sum is 47.

The spelling of 99992300000033 in words is "ninety-nine trillion, nine hundred ninety-two billion, three hundred million, thirty-three", and thus it is an aban number.