Base | Representation |
---|---|
bin | 1001000110000100101011… |
… | …0111000111010011110011 |
3 | 1022101222121000000010220012 |
4 | 2101201022313013103303 |
5 | 2302314334043430211 |
6 | 33133524155205135 |
7 | 2051320555026515 |
oct | 221411267072363 |
9 | 38358530003805 |
10 | 9999939826931 |
11 | 3205a5037510a |
12 | 115607b7467ab |
13 | 576cb484a862 |
14 | 267ddd147bb5 |
15 | 1251c4a08d8b |
hex | 9184adc74f3 |
9999939826931 has 2 divisors, whose sum is σ = 9999939826932. Its totient is φ = 9999939826930.
The previous prime is 9999939826889. The next prime is 9999939826969. The reversal of 9999939826931 is 1396289399999.
9999939826931 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-9999939826931 is a prime.
It is a super-2 number, since 2×99999398269312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (9999939826991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4999969913465 + 4999969913466.
It is an arithmetic number, because the mean of its divisors is an integer number (4999969913466).
Almost surely, 29999939826931 is an apocalyptic number.
9999939826931 is a deficient number, since it is larger than the sum of its proper divisors (1).
9999939826931 is an equidigital number, since it uses as much as digits as its factorization.
9999939826931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4132485216, while the sum is 86.
The spelling of 9999939826931 in words is "nine trillion, nine hundred ninety-nine billion, nine hundred thirty-nine million, eight hundred twenty-six thousand, nine hundred thirty-one".
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