Base | Representation |
---|---|
bin | 11101000110101000100… |
… | …10011000001011100011 |
3 | 10112121011022010121011111 |
4 | 32203110102120023203 |
5 | 112340441431000344 |
6 | 2043220233524151 |
7 | 132150532516423 |
oct | 16432422301343 |
9 | 3477138117144 |
10 | 999994000099 |
11 | 3561055a80a6 |
12 | 14197bb73657 |
13 | 733b6c778c3 |
14 | 36585724483 |
15 | 1b02ae7d834 |
hex | e8d44982e3 |
999994000099 has 2 divisors, whose sum is σ = 999994000100. Its totient is φ = 999994000098.
The previous prime is 999994000073. The next prime is 999994000121. The reversal of 999994000099 is 990000499999.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 999994000099 - 25 = 999994000067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 999993999998 and 999994000043.
It is not a weakly prime, because it can be changed into another prime (999994004099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499997000049 + 499997000050.
It is an arithmetic number, because the mean of its divisors is an integer number (499997000050).
Almost surely, 2999994000099 is an apocalyptic number.
999994000099 is a deficient number, since it is larger than the sum of its proper divisors (1).
999994000099 is an equidigital number, since it uses as much as digits as its factorization.
999994000099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19131876, while the sum is 67.
The spelling of 999994000099 in words is "nine hundred ninety-nine billion, nine hundred ninety-four million, ninety-nine", and thus it is an aban number.
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