Search a number
-
+
999995555511107 is a prime number
BaseRepresentation
bin1110001101011111011001101…
…1110111001111101101000011
311212010200122022122001212021022
43203113312123313033231003
52022032411344202323412
613502451341034420055
7420430203040532111
oct34327663367175503
94763618278055238
10999995555511107
1126a6a180828a321
12941a5a0829162b
1333bca23a31889c
14138d20864daab1
157a922a5025a72
hex38d7d9bdcfb43

999995555511107 has 2 divisors, whose sum is σ = 999995555511108. Its totient is φ = 999995555511106.

The previous prime is 999995555511061. The next prime is 999995555511163. The reversal of 999995555511107 is 701115555599999.

It is a weak prime.

It is an emirp because it is prime and its reverse (701115555599999) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 999995555511107 - 234 = 999978375641923 is a prime.

It is a super-2 number, since 2×9999955555111072 (a number of 31 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (999995555516107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499997777755553 + 499997777755554.

It is an arithmetic number, because the mean of its divisors is an integer number (499997777755554).

Almost surely, 2999995555511107 is an apocalyptic number.

999995555511107 is a deficient number, since it is larger than the sum of its proper divisors (1).

999995555511107 is an equidigital number, since it uses as much as digits as its factorization.

999995555511107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1291696875, while the sum is 80.

The spelling of 999995555511107 in words is "nine hundred ninety-nine trillion, nine hundred ninety-five billion, five hundred fifty-five million, five hundred eleven thousand, one hundred seven".