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999999273000073 is a prime number
BaseRepresentation
bin1110001101011111100111100…
…1011100010101110010001001
311212010200222220201011212102211
43203113321321130111302021
52022032442002342000243
613502453153553225121
7420430364130626263
oct34327717134256211
94763628821155384
10999999273000073
1126a6a3345754855
12941a66852621a1
1333bca6b05539b8
14138d231a110b33
157a92421593d9d
hex38d7e79715c89

999999273000073 has 2 divisors, whose sum is σ = 999999273000074. Its totient is φ = 999999273000072.

The previous prime is 999999272999999. The next prime is 999999273000113. The reversal of 999999273000073 is 370000372999999.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 926554150179904 + 73445122820169 = 30439352^2 + 8570013^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-999999273000073 is a prime.

It is not a weakly prime, because it can be changed into another prime (999999273007073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999636500036 + 499999636500037.

It is an arithmetic number, because the mean of its divisors is an integer number (499999636500037).

Almost surely, 2999999273000073 is an apocalyptic number.

It is an amenable number.

999999273000073 is a deficient number, since it is larger than the sum of its proper divisors (1).

999999273000073 is an equidigital number, since it uses as much as digits as its factorization.

999999273000073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 468730962, while the sum is 76.

The spelling of 999999273000073 in words is "nine hundred ninety-nine trillion, nine hundred ninety-nine billion, two hundred seventy-three million, seventy-three", and thus it is an aban number.