99999931403 has 2 divisors, whose sum is σ = 99999931404. Its totient is φ = 99999931402.

The previous prime is 99999931387. The next prime is 99999931411. The reversal of 99999931403 is 30413999999.

It is a strong prime.

It is an emirp because it is prime and its reverse (30413999999) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99999931403 - 2⁴ = 99999931387 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 99999931403.

It is not a weakly prime, because it can be changed into another prime (99999931483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49999965701 + 49999965702.

It is an arithmetic number, because the mean of its divisors is an integer number (49999965702).

Almost surely, 2^99999931403 is an apocalyptic number.

99999931403 is a deficient number, since it is larger than the sum of its proper divisors (1).

99999931403 is an equidigital number, since it uses as much as digits as its factorization.

99999931403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19131876, while the sum is 65.

The spelling of 99999931403 in words is "ninety-nine billion, nine hundred ninety-nine million, nine hundred thirty-one thousand, four hundred three".