Base | Representation |
---|---|
bin | 10110101111001100010001… |
… | …000100101101011011011111 |
3 | 111010001220111122010120211121 |
4 | 112233030101010231123133 |
5 | 101101400010030000340 |
6 | 552403212001031411 |
7 | 30030522320142112 |
oct | 2657142104553337 |
9 | 433056448116747 |
10 | 100000010000095 |
11 | 29954847717417 |
12 | b270809025567 |
13 | 43a4c6423786a |
14 | 1a9a052296579 |
15 | b8636a5e794a |
hex | 5af31112d6df |
100000010000095 has 4 divisors (see below), whose sum is σ = 120000012000120. Its totient is φ = 80000008000072.
The previous prime is 100000010000063. The next prime is 100000010000147. The reversal of 100000010000095 is 590000010000001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100000010000095 - 25 = 100000010000063 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10000001000005 + ... + 10000001000014.
It is an arithmetic number, because the mean of its divisors is an integer number (30000003000030).
Almost surely, 2100000010000095 is an apocalyptic number.
100000010000095 is a deficient number, since it is larger than the sum of its proper divisors (20000002000025).
100000010000095 is an equidigital number, since it uses as much as digits as its factorization.
100000010000095 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20000002000024.
The product of its (nonzero) digits is 45, while the sum is 16.
Adding to 100000010000095 its reverse (590000010000001), we get a palindrome (690000020000096).
The spelling of 100000010000095 in words is "one hundred trillion, ten million, ninety-five", and thus it is an aban number.
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