10000012013 has 4 divisors (see below), whose sum is σ = 10434795168. Its totient is φ = 9565228860.

The previous prime is 10000012007. The next prime is 10000012019. The reversal of 10000012013 is 31021000001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31021000001 = 68767 ⋅451103.

It is an interprime number because it is at equal distance from previous prime (10000012007) and next prime (10000012019).

It is a cyclic number.

It is not a de Polignac number, because 10000012013 - 2⁴ = 10000011997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10000012019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217391543 + ... + 217391588.

It is an arithmetic number, because the mean of its divisors is an integer number (2608698792).

Almost surely, 2^10000012013 is an apocalyptic number.

It is an amenable number.

10000012013 is a deficient number, since it is larger than the sum of its proper divisors (434783155).

10000012013 is an equidigital number, since it uses as much as digits as its factorization.

10000012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434783154.

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 10000012013 its reverse (31021000001), we get a palindrome (41021012014).

The spelling of 10000012013 in words is "ten billion, twelve thousand, thirteen".