1000040311317 has 4 divisors (see below), whose sum is σ = 1333387081760. Its totient is φ = 666693540876.

The previous prime is 1000040311219. The next prime is 1000040311337. The reversal of 1000040311317 is 7131130400001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1000040311317 - 2¹¹ = 1000040309269 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1000040311293 and 1000040311302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000040311337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166673385217 + ... + 166673385222.

It is an arithmetic number, because the mean of its divisors is an integer number (333346770440).

Almost surely, 2^{1000040311317} is an apocalyptic number.

It is an amenable number.

1000040311317 is a deficient number, since it is larger than the sum of its proper divisors (333346770443).

1000040311317 is an equidigital number, since it uses as much as digits as its factorization.

1000040311317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333346770442.

The product of its (nonzero) digits is 252, while the sum is 21.

Adding to 1000040311317 its reverse (7131130400001), we get a palindrome (8131170711318).

The spelling of 1000040311317 in words is "one trillion, forty million, three hundred eleven thousand, three hundred seventeen".