1000103143 has 4 divisors (see below), whose sum is σ = 1077034168. Its totient is φ = 923172120.

The previous prime is 1000103141. The next prime is 1000103173. The reversal of 1000103143 is 3413010001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3413010001 = 24763 ⋅137827.

It is not a de Polignac number, because 1000103143 - 2¹ = 1000103141 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 76931011 = 1000103143 / (1 + 0 + 0 + 0 + 1 + 0 + 3 + 1 + 4 + 3).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000103141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38465493 + ... + 38465518.

It is an arithmetic number, because the mean of its divisors is an integer number (269258542).

Almost surely, 2^1000103143 is an apocalyptic number.

1000103143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1000103143 is a deficient number, since it is larger than the sum of its proper divisors (76931025).

1000103143 is an equidigital number, since it uses as much as digits as its factorization.

1000103143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76931024.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1000103143 is about 31624.4073936572. The cubic root of 1000103143 is about 1000.0343798180.

Adding to 1000103143 its reverse (3413010001), we get a palindrome (4413113144).

The spelling of 1000103143 in words is "one billion, one hundred three thousand, one hundred forty-three".