10001241321433 has 4 divisors (see below), whose sum is σ = 10142103875328. Its totient is φ = 9860378767540.

The previous prime is 10001241321419. The next prime is 10001241321473. The reversal of 10001241321433 is 33412314210001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10001241321433 - 2²¹ = 10001239224281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10001241321398 and 10001241321407.

It is not an unprimeable number, because it can be changed into a prime (10001241321473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70431276841 + ... + 70431276982.

It is an arithmetic number, because the mean of its divisors is an integer number (2535525968832).

Almost surely, 2^{10001241321433} is an apocalyptic number.

It is an amenable number.

10001241321433 is a deficient number, since it is larger than the sum of its proper divisors (140862553895).

10001241321433 is an equidigital number, since it uses as much as digits as its factorization.

10001241321433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140862553894.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10001241321433 its reverse (33412314210001), we get a palindrome (43413555531434).

The spelling of 10001241321433 in words is "ten trillion, one billion, two hundred forty-one million, three hundred twenty-one thousand, four hundred thirty-three".