100013100111101 has 4 divisors (see below), whose sum is σ = 100013127000000. Its totient is φ = 100013073222204.

The previous prime is 100013100111077. The next prime is 100013100111179. The reversal of 100013100111101 is 101111001310001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100013100111101 - 2⁶ = 100013100111037 is a prime.

It is a super-2 number, since 2×100013100111101² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100013100111401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6756101 + ... + 15673898.

It is an arithmetic number, because the mean of its divisors is an integer number (25003281750000).

Almost surely, 2^{100013100111101} is an apocalyptic number.

It is an amenable number.

100013100111101 is a deficient number, since it is larger than the sum of its proper divisors (26888899).

100013100111101 is an equidigital number, since it uses as much as digits as its factorization.

100013100111101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26888898.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 100013100111101 its reverse (101111001310001), we get a palindrome (201124101421102).

The spelling of 100013100111101 in words is "one hundred trillion, thirteen billion, one hundred million, one hundred eleven thousand, one hundred one".