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100013102023 = 257547711437
BaseRepresentation
bin101110100100100111…
…1101101001111000111
3100120011002021222211211
41131021033231033013
53114311323231043
6113540111512251
710140263224552
oct1351117551707
9316132258754
10100013102023
113946287491a
1217472228687
13957b449213
144baaab1699
152905476a9d
hex17493ed3c7

100013102023 has 8 divisors (see below), whose sum is σ = 100585950192. Its totient is φ = 99441678336.

The previous prime is 100013102011. The next prime is 100013102047. The reversal of 100013102023 is 320201310001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100013102023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100013101994 and 100013102012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100013102003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215140 + ... + 496297.

It is an arithmetic number, because the mean of its divisors is an integer number (12573243774).

Almost surely, 2100013102023 is an apocalyptic number.

100013102023 is a deficient number, since it is larger than the sum of its proper divisors (572848169).

100013102023 is an equidigital number, since it uses as much as digits as its factorization.

100013102023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 712241.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 100013102023 its reverse (320201310001), we get a palindrome (420214412024).

The spelling of 100013102023 in words is "one hundred billion, thirteen million, one hundred two thousand, twenty-three".

Divisors: 1 257 547 140579 711437 182839309 389156039 100013102023