Search a number
-
+
100013112023 = 119092101093
BaseRepresentation
bin101110100100100111…
…1101111101011010111
3100120011002022111120012
41131021033233223113
53114311324041043
6113540112030435
710140263265656
oct1351117575327
9316132274505
10100013112023
1139462881390
121747223241b
13957b450936
144baaab519d
152905479a18
hex17493efad7

100013112023 has 4 divisors (see below), whose sum is σ = 109105213128. Its totient is φ = 90921010920.

The previous prime is 100013111953. The next prime is 100013112037. The reversal of 100013112023 is 320211310001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100013112023 - 218 = 100012849879 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100013111989 and 100013112007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100013114023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4546050536 + ... + 4546050557.

It is an arithmetic number, because the mean of its divisors is an integer number (27276303282).

Almost surely, 2100013112023 is an apocalyptic number.

100013112023 is a deficient number, since it is larger than the sum of its proper divisors (9092101105).

100013112023 is an equidigital number, since it uses as much as digits as its factorization.

100013112023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9092101104.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100013112023 its reverse (320211310001), we get a palindrome (420224422024).

The spelling of 100013112023 in words is "one hundred billion, thirteen million, one hundred twelve thousand, twenty-three".

Divisors: 1 11 9092101093 100013112023