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10001340304402 = 25000670152201
BaseRepresentation
bin1001000110001001111001…
…0101100000110000010010
31022102010012121020202211011
42101202132111200300102
52302330221104220102
633134315144241134
72051400351631306
oct221423625406022
938363177222734
1010001340304402
1132065a995a607
1211563b07701aa
13577178a35755
142680d3141d06
151252579452d7
hex9189e560c12

10001340304402 has 4 divisors (see below), whose sum is σ = 15002010456606. Its totient is φ = 5000670152200.

The previous prime is 10001340304399. The next prime is 10001340304411. The reversal of 10001340304402 is 20440304310001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9874432654321 + 126907650081 = 3142361^2 + 356241^2 .

It is a super-3 number, since 3×100013403044023 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2500335076099 + ... + 2500335076102.

Almost surely, 210001340304402 is an apocalyptic number.

10001340304402 is a deficient number, since it is larger than the sum of its proper divisors (5000670152204).

10001340304402 is an equidigital number, since it uses as much as digits as its factorization.

10001340304402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5000670152203.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 10001340304402 its reverse (20440304310001), we get a palindrome (30441644614403).

The spelling of 10001340304402 in words is "ten trillion, one billion, three hundred forty million, three hundred four thousand, four hundred two".

Divisors: 1 2 5000670152201 10001340304402