10001351400013 has 4 divisors (see below), whose sum is σ = 10036691864608. Its totient is φ = 9966010935420.

The previous prime is 10001351399999. The next prime is 10001351400017. The reversal of 10001351400013 is 31000415310001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10001351400013 - 2⁵ = 10001351399981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001351400017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17670231873 + ... + 17670232438.

It is an arithmetic number, because the mean of its divisors is an integer number (2509172966152).

Almost surely, 2^{10001351400013} is an apocalyptic number.

It is an amenable number.

10001351400013 is a deficient number, since it is larger than the sum of its proper divisors (35340464595).

10001351400013 is an equidigital number, since it uses as much as digits as its factorization.

10001351400013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35340464594.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 10001351400013 its reverse (31000415310001), we get a palindrome (41001766710014).

The spelling of 10001351400013 in words is "ten trillion, one billion, three hundred fifty-one million, four hundred thousand, thirteen".