10001400133341 has 4 divisors (see below), whose sum is σ = 13335200177792. Its totient is φ = 6667600088892.

The previous prime is 10001400133331. The next prime is 10001400133409. The reversal of 10001400133341 is 14333100410001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10001400133341 - 2¹¹ = 10001400131293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001400133301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1666900022221 + ... + 1666900022226.

It is an arithmetic number, because the mean of its divisors is an integer number (3333800044448).

Almost surely, 2^{10001400133341} is an apocalyptic number.

It is an amenable number.

10001400133341 is a deficient number, since it is larger than the sum of its proper divisors (3333800044451).

10001400133341 is an equidigital number, since it uses as much as digits as its factorization.

10001400133341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3333800044450.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10001400133341 its reverse (14333100410001), we get a palindrome (24334500543342).

The spelling of 10001400133341 in words is "ten trillion, one billion, four hundred million, one hundred thirty-three thousand, three hundred forty-one".