10001401141341 has 4 divisors (see below), whose sum is σ = 13335201521792. Its totient is φ = 6667600760892.

The previous prime is 10001401141289. The next prime is 10001401141399. The reversal of 10001401141341 is 14314110410001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10001401141341 - 2⁴³ = 1205308119133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001401141141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1666900190221 + ... + 1666900190226.

It is an arithmetic number, because the mean of its divisors is an integer number (3333800380448).

Almost surely, 2^{10001401141341} is an apocalyptic number.

It is an amenable number.

10001401141341 is a deficient number, since it is larger than the sum of its proper divisors (3333800380451).

10001401141341 is an equidigital number, since it uses as much as digits as its factorization.

10001401141341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3333800380450.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 10001401141341 its reverse (14314110410001), we get a palindrome (24315511551342).

The spelling of 10001401141341 in words is "ten trillion, one billion, four hundred one million, one hundred forty-one thousand, three hundred forty-one".