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1000200132314 = 2500100066157
BaseRepresentation
bin11101000111000001001…
…00101101011011011010
310112121200200000012101222
432203200210231123122
5112341402213213224
62043252520012042
7132155614564115
oct16434044553332
93477620005358
101000200132314
113562009992a9
12141a19001022
137341a89b126
14365a4c6157c
151b03e0e9b5e
hexe8e092d6da

1000200132314 has 4 divisors (see below), whose sum is σ = 1500300198474. Its totient is φ = 500100066156.

The previous prime is 1000200132293. The next prime is 1000200132359. The reversal of 1000200132314 is 4132310020001.

1000200132314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 537997311289 + 462202821025 = 733483^2 + 679855^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1000200132292 and 1000200132301.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250050033077 + ... + 250050033080.

Almost surely, 21000200132314 is an apocalyptic number.

1000200132314 is a deficient number, since it is larger than the sum of its proper divisors (500100066160).

1000200132314 is an equidigital number, since it uses as much as digits as its factorization.

1000200132314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 500100066159.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1000200132314 its reverse (4132310020001), we get a palindrome (5132510152315).

The spelling of 1000200132314 in words is "one trillion, two hundred million, one hundred thirty-two thousand, three hundred fourteen".

Divisors: 1 2 500100066157 1000200132314