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100021312023 = 335992870299
BaseRepresentation
bin101110100100110111…
…1000001101000010111
3100120011122202002211220
41131021233001220113
53114320423441043
6113541003501423
710140423060453
oct1351157015027
9316148662756
10100021312023
1139467472146
1217474b27873
1395800620c9
144babc0b663
152906049483
hex1749bc1a17

100021312023 has 8 divisors (see below), whose sum is σ = 133733232000. Its totient is φ = 66495133368.

The previous prime is 100021312021. The next prime is 100021312037. The reversal of 100021312023 is 320213120001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100021312023 - 21 = 100021312021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100021311993 and 100021312011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100021312021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46434073 + ... + 46436226.

It is an arithmetic number, because the mean of its divisors is an integer number (16716654000).

Almost surely, 2100021312023 is an apocalyptic number.

100021312023 is a deficient number, since it is larger than the sum of its proper divisors (33711919977).

100021312023 is an equidigital number, since it uses as much as digits as its factorization.

100021312023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92870661.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 100021312023 its reverse (320213120001), we get a palindrome (420234432024).

The spelling of 100021312023 in words is "one hundred billion, twenty-one million, three hundred twelve thousand, twenty-three".

Divisors: 1 3 359 1077 92870299 278610897 33340437341 100021312023