Base | Representation |
---|---|
bin | 10010101000010110… |
… | …01000101110010101 |
3 | 221211001210100201121 |
4 | 21110023020232111 |
5 | 130441021440203 |
6 | 4332300323541 |
7 | 502601534113 |
oct | 112413105625 |
9 | 27731710647 |
10 | 10002140053 |
11 | 4272a46954 |
12 | 1b318435b1 |
13 | c35289589 |
14 | 6ac55cab3 |
15 | 3d81820bd |
hex | 2542c8b95 |
10002140053 has 4 divisors (see below), whose sum is σ = 10002667948. Its totient is φ = 10001612160.
The previous prime is 10002139997. The next prime is 10002140069. The reversal of 10002140053 is 35004120001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8183373444 + 1818766609 = 90462^2 + 42647^2 .
It is a cyclic number.
It is not a de Polignac number, because 10002140053 - 29 = 10002139541 is a prime.
It is a super-3 number, since 3×100021400533 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10002140653) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234426 + ... + 273787.
It is an arithmetic number, because the mean of its divisors is an integer number (2500666987).
Almost surely, 210002140053 is an apocalyptic number.
It is an amenable number.
10002140053 is a deficient number, since it is larger than the sum of its proper divisors (527895).
10002140053 is an equidigital number, since it uses as much as digits as its factorization.
10002140053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 527894.
The product of its (nonzero) digits is 120, while the sum is 16.
Adding to 10002140053 its reverse (35004120001), we get a palindrome (45006260054).
The spelling of 10002140053 in words is "ten billion, two million, one hundred forty thousand, fifty-three".
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