Base | Representation |
---|---|
bin | 101110100100110111… |
… | …1110101001010101011 |
3 | 100120011200010211102010 |
4 | 1131021233311022223 |
5 | 3114321002214430 |
6 | 113541012211003 |
7 | 10140424630053 |
oct | 1351157651253 |
9 | 316150124363 |
10 | 100021523115 |
11 | 394675a67a8 |
12 | 17475009a63 |
13 | 9580107207 |
14 | 4babc64563 |
15 | 290608bcb0 |
hex | 1749bf52ab |
100021523115 has 32 divisors (see below), whose sum is σ = 160865049600. Its totient is φ = 53068659840.
The previous prime is 100021523113. The next prime is 100021523141. The reversal of 100021523115 is 511325120001.
It is not a de Polignac number, because 100021523115 - 21 = 100021523113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100021523091 and 100021523100.
It is not an unprimeable number, because it can be changed into a prime (100021523113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2245026 + ... + 2289144.
It is an arithmetic number, because the mean of its divisors is an integer number (5027032800).
Almost surely, 2100021523115 is an apocalyptic number.
100021523115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
100021523115 is a deficient number, since it is larger than the sum of its proper divisors (60843526485).
100021523115 is a wasteful number, since it uses less digits than its factorization.
100021523115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44907.
The product of its (nonzero) digits is 300, while the sum is 21.
Adding to 100021523115 its reverse (511325120001), we get a palindrome (611346643116).
The spelling of 100021523115 in words is "one hundred billion, twenty-one million, five hundred twenty-three thousand, one hundred fifteen".
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