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1000313312040 = 2332573743249497
BaseRepresentation
bin11101000111001110101…
…00011101001100101000
310112121222112222022210200
432203213110131030220
5112342120201441130
62043312041512200
7132161460601140
oct16434724351450
93477875868720
101000313312040
11356259871969
12141a4aaa2660
1373438177893
14365b5cc3920
151b049004760
hexe8e751d328

1000313312040 has 384 divisors, whose sum is σ = 3904623740160. Its totient is φ = 217289060352.

The previous prime is 1000313312039. The next prime is 1000313312051. The reversal of 1000313312040 is 402133130001.

1000313312040 is a `hidden beast` number, since 1 + 0 + 0 + 0 + 313 + 312 + 0 + 40 = 666.

1000313312040 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3884572 + ... + 4134068.

It is an arithmetic number, because the mean of its divisors is an integer number (10168290990).

Almost surely, 21000313312040 is an apocalyptic number.

1000313312040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1000313312040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1952311870080).

1000313312040 is an abundant number, since it is smaller than the sum of its proper divisors (2904310428120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1000313312040 is a wasteful number, since it uses less digits than its factorization.

1000313312040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 249601 (or 249594 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 1000313312040 its reverse (402133130001), we get a palindrome (1402446442041).

The spelling of 1000313312040 in words is "one trillion, three hundred thirteen million, three hundred twelve thousand, forty".