100034143111 has 4 divisors (see below), whose sum is σ = 114324734992. Its totient is φ = 85743551232.

The previous prime is 100034143073. The next prime is 100034143117. The reversal of 100034143111 is 111341430001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111341430001 = 273313 ⋅407377.

It is a cyclic number.

It is not a de Polignac number, because 100034143111 - 2⁷ = 100034142983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100034143117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7145295930 + ... + 7145295943.

It is an arithmetic number, because the mean of its divisors is an integer number (28581183748).

Almost surely, 2^100034143111 is an apocalyptic number.

100034143111 is a deficient number, since it is larger than the sum of its proper divisors (14290591881).

100034143111 is an equidigital number, since it uses as much as digits as its factorization.

100034143111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14290591880.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 100034143111 its reverse (111341430001), we get a palindrome (211375573112).

The spelling of 100034143111 in words is "one hundred billion, thirty-four million, one hundred forty-three thousand, one hundred eleven".