1000343413 has 4 divisors (see below), whose sum is σ = 1000412140. Its totient is φ = 1000274688.

The previous prime is 1000343411. The next prime is 1000343417. The reversal of 1000343413 is 3143430001.

1000343413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 513611569 + 486731844 = 22663^2 + 22062^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000343413 - 2¹ = 1000343411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000343411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2970 + ... + 44827.

It is an arithmetic number, because the mean of its divisors is an integer number (250103035).

Almost surely, 2^1000343413 is an apocalyptic number.

It is an amenable number.

1000343413 is a deficient number, since it is larger than the sum of its proper divisors (68727).

1000343413 is an equidigital number, since it uses as much as digits as its factorization.

1000343413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68726.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 1000343413 is about 31628.2059718853. The cubic root of 1000343413 is about 1000.1144578989.

Adding to 1000343413 its reverse (3143430001), we get a palindrome (4143773414).

The spelling of 1000343413 in words is "one billion, three hundred forty-three thousand, four hundred thirteen".