10004000013 has 60 divisors (see below), whose sum is σ = 18143189152. Its totient is φ = 5380214400.

The previous prime is 10004000003. The next prime is 10004000033. The reversal of 10004000013 is 31000040001.

10004000013 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10004000013 - 2⁵ = 10003999981 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10003999959 and 10004000004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10004000003) by changing a digit.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 133338 + ... + 194388.

Almost surely, 2^10004000013 is an apocalyptic number.

It is an amenable number.

10004000013 is a deficient number, since it is larger than the sum of its proper divisors (8139189139).

10004000013 is an equidigital number, since it uses as much as digits as its factorization.

10004000013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61104 (or 61078 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 10004000013 its reverse (31000040001), we get a palindrome (41004040014).

The spelling of 10004000013 in words is "ten billion, four million, thirteen", and thus it is an aban number.